x^2-29=3x

Solution for x^2-29=3x equation:

x^2-29=3x

We move all terms to the left:

x^2-29-(3x)=0

a = 1; b = -3; c = -29;
Δ = b2-4ac
Δ = -32-4·1·(-29)
Δ = 125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{125}=\sqrt{25*5}=\sqrt{25}*\sqrt{5}=5\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-5\sqrt{5}}{2*1}=\frac{3-5\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+5\sqrt{5}}{2*1}=\frac{3+5\sqrt{5}}{2}
$